While loop is continuous.

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jack bennet
jack bennet 2012 年 8 月 28 日
Im trying to write a homeloan function that calcs certain values(deposit, interest etc) and displays an error message if the deposit is less that %20 of the house price.
Only problem is, the function loops continuosly. Any idea how to fix this?? My SCRIPT is below. cheers
function [monthlyPayment, interest] = homeloan(price, deposit, intRate, lengthOfLoan)
% for deposit while using a while loop
deposit <= ((300000)/ 5);
while deposit < 300000
disp('error');
deposit= ((300000)/ 5); % do not forget to do this, otherwise we would loop forever
%monthly payment
monthlyPayment = (((price - deposit)*intRate)*((1 + intRate)^lengthOfLoan))/(((1 + intRate)^lengthOfLoan) - 1)
% interest
interest = (monthlyPayment * lengthOfLoan) - ( price - deposit)
end
  1 件のコメント
Azzi Abdelmalek
Azzi Abdelmalek 2012 年 8 月 28 日
編集済み: Azzi Abdelmalek 2012 年 8 月 28 日
deposit= ((300000)/ 5); % if you do this, you will loop forever
can you post the full code

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回答 (3 件)

Walter Roberson
Walter Roberson 2012 年 8 月 28 日
deposit <= ((300000)/ 5);
is a logical test, followed by throwing away the result. It is not an assignment.

Arthur
Arthur 2012 年 8 月 28 日
You're not changing the value of deposit in the loop, but always setting it at 300000/5. So deposit is always smaller than 300000, and the loop will run forever.

Image Analyst
Image Analyst 2012 年 8 月 28 日
Try this. Just check to see if the deposit is big enough and warn user if it's not:
function [monthlyPayment, interest] = homeloan(price, deposit, intRate, lengthOfLoan)
monthlyPayment = [];
interest = [];
minDeposit = price * 0.2;
if deposit < minDeposit
warningMessage = sprintf('Error: your deposit of %.2f is less than the required deposit of %.2f, which is 20%%of %.2f',...
deposit, minDeposit, price);
uiwait(warndlg(warningMessage));
else
% Calculate monthly payment
monthlyPayment = (((price - deposit)*intRate)*((1 + intRate)^lengthOfLoan))/(((1 + intRate)^lengthOfLoan) - 1)
% Calculate interest
interest = (monthlyPayment * lengthOfLoan) - ( price - deposit)
end

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