Why are my array dimensions being changed?

I have a 3D array cart = s x 3 x p double, where s and p are variables chosen as integers by an optimiser. I'm converting this array to the array sph = s x 3 x p through cart2sph;
[sph(:,1,:), sph(:,2,:), sph(:,3,:)] = cart2sph(cart(:,1,:), cart(:,2,:), cart(:,3,:));
This works fine, unless the case happens to be the optimiser choses to set s = 1. Instead of outputting sph = 1 x 3 x p, it outputs sph = p x 3, which causes issues with my code calling the function I do this in.
It only happens with s, I've tried limiting p to 1 only it seems to run fine, can anyone help?

 採用された回答

Star Strider
Star Strider 2019 年 6 月 19 日

1 投票

You can add the missing dimension.
Experiment with this:
x1 = rand(3,4);
x2(1,:,:) = x1;
To check:
x1s = size(x1)
x2s = size(x2)
produces:
x1s =
3 4
x2s =
1 3 4
You will have to set up the appropriate tests to check the dimensions, then do the assignment.

4 件のコメント

Scott Hunter
Scott Hunter 2019 年 6 月 19 日
I think I did something similar, essentially I checked if s == 1, then permuted the array;
if s == 1
permute(sph, [3 2 1]);
end
Star Strider
Star Strider 2019 年 6 月 19 日
That wasn’t in the code you posted, so I didn’t see it.
The optimiser could be using the squeeze function to eliminate the singleton dimensions. If that’s the situation, you would have to add it back.
Scott Hunter
Scott Hunter 2019 年 6 月 19 日
No no as in I adder it after your comment, it gave me the idea. Thanks!
Star Strider
Star Strider 2019 年 6 月 19 日
As always, my pleasure!

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