Vector operations not working correctly
1 回表示 (過去 30 日間)
古いコメントを表示
I have the following code
cvPredictions = (pval < epsilon)== 1; % Anomaly
cvPredictions = (pval > epsilon)== 0; % Not an anomaly
In the above code, pval is a vector, epsilon is a scalar and cvPredictions will be vector and each element of a vector will be 0 or 1
I want the follwoing
a) if any element of pval is less than epsilon, then, I want the corresponding element of cvPredictions to be 1
b) if any element of pval is greater than epsilon, then, I want the corresponding element of cvPredictions to be 0
I do not want to give a for loop. I do not think the above code is correct. Can anyone suggest me how to achieve a and b in simple one or 2 liner vectorized approach?
0 件のコメント
採用された回答
Andrei Bobrov
2019 年 6 月 16 日
cvPredictions = pval < epsilon;
2 件のコメント
Andrei Bobrov
2019 年 6 月 16 日
>> pval = randi(100,6,1)
pval =
82
91
13
92
64
10
>> epsilon = 50
epsilon =
50
>> cvPredictions = pval < epsilon
cvPredictions =
6×1 logical array
0
0
1
0
0
1
>>
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Creating and Concatenating Matrices についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!