How to plot sine graph by using for loop?
18 ビュー (過去 30 日間)
古いコメントを表示
I tried to use a for loop to plot a sine graph. The values are generated but then when I try to graph them, I get either an error or no graph. Here's my code:
for i = 0:0.1:2*pi
m=sin(i);
n=i;
plot(n,m,'-r');
hold on
end
2 件のコメント
採用された回答
Alex Mcaulley
2019 年 6 月 5 日
You don't need a loop, just:
theta = 0:0.1:2*pi;
plot(theta,sin(theta))
6 件のコメント
AZEEM IMTIAZ
2019 年 8 月 4 日
you need to define t as a continuous variable in the first line then apply for loop on the frequency as discrete values. so that each frequency point will sweep over the time that you have defined in the first line. hope this helps!
t=0:0.04:5;
hold on
for f=[0.7 1 1.5 2]
y=cos(2*pi*f*t);
plot(t,y)
end
その他の回答 (1 件)
Mohammad Alhashash
2019 年 6 月 5 日
maybe that is what you need.
t= 0:0.01:2*pi;
m =sin(t);
t_plot = NaN(1,length(t));
m_plot = NaN(1,length(m));
u = 1;
for i = 1:length(t)
cla
t_plot(i) = t(u);
m_plot(i) = m(u);
plot(t_plot,m_plot)
drawnow
u = u + 1;
end
参考
カテゴリ
Help Center および File Exchange で Graphics Performance についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!