Align different starting point to zero

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Jaehwi Bong
Jaehwi Bong 2019 年 6 月 4 日
コメント済み: Jaehwi Bong 2019 年 6 月 4 日
I have a matrix , 7096*3 double.
At a first column, numbers represent same particles with different number. I have 168 particles and each of them has different starting time points(second column) with intensity value(third column). In the case of 40th particles, it starts from 2.1960 (see, the matrix, 40 from first column and 2.196 from second column).
I'd like to align those data to zero as the starting point. I need to find inital value or minimum value of time column of each particle and substract them. And make new matrix, probably. How can I do for that?
40 2.196 51950
40 3.294 51728
40 4.392 50899
40 5.490 50869
40 6.588 51741
-> What I want to do is
40 0 51950
40 1.098 51728
40 2.196 50899
40 3.294 50869
40 4.392 51741
number=unique(B(:,1));
tn=length(unique(B(:,1)));
for k=1:tn
B(B(:,1)==number(k),2)-min(B(B(:,1)==number(k),2));
end

採用された回答

Sayyed Ahmad
Sayyed Ahmad 2019 年 6 月 4 日
try with find and index
for i=1:tn
ind=find(B(:,1)==number(i))
y=min(B(ind,2));
B(ind,2)=b(ind,2)-y;
end
  1 件のコメント
Jaehwi Bong
Jaehwi Bong 2019 年 6 月 4 日
Thank you very much!

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