?1(?) = 1 + 2?−1 + 3?−2 and ?2(?) = 4 + 5?−1 + 6?−2. Use MATLAB to generate a sequence ?3(?) = ?1(?)?2(?). Utilize either the multiplication property or the convolution property. send me some other proper code if anyone have

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Umar Bhai
Umar Bhai 2019 年 5 月 28 日
コメント済み: Umar Bhai 2019 年 5 月 28 日
>> x1=[1 2 3];
>> x2=[4 5 6];
>> x3=conv(x1,x2)
Output:
x3 =
4 13 28 27 18
  3 件のコメント
Raj
Raj 2019 年 5 月 28 日
So,
x1(?) = 1 + 2?−1 + 3?−2 = 5z-2?
and x2(?) = 4 + 5?−1 + 6?−2= 11z+1?
Is that so?
then
x1=[5 -2]
x2=[11 1]
x3=conv(x1,x2)
is that what you are looking for?
Umar Bhai
Umar Bhai 2019 年 5 月 28 日
no no this (1 + 2?−1 + 3?−2) is not 2z minus 1 + 3zminus 2..
here -1 and -2 are inverse power of z like below;
this is 2z raised to the power -1 + 3z raised to the power -2

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