how to replace a column in a matrix

I wanna know how to replace a column in below condition:

Assmuing I had a 5*5 matrix, I wanna replace each column by zeros(5,1) for 5 times. I don't mean to get a 5*5 all 0 element matrix eventually. I want to get 5 matrix with their 1st,2nd,3rd,4th,5th column be replaced individually. How could I code for this? Thanks.

[James Tursa]

What have you done so far? What specific problems are you having with your code? Can you write a loop and put the results into a cell array?

[ZHEN XU]

A = rand(5,5);

B = zeros(5,1);

m = 5;

for i = 1:m

A(:,i) = B;

end

This is what I wrote, but It gave me a matrix with all column got replaced... I wanna 5 matrix outcome, only one colume got replaced at a time

Answer 1

[James Tursa]

Instead of replacing all of the columns of A, use a different variable for the result. E.g., a cell array named C. So instead of this:

A(:,i) = B; 

you could have this

C{i} = A;
C{i}(:,i) = B;

Then each of C{1}, C{2}, etc contain your matrices

[ZHEN XU]

Thank you. It works.