is there a jump of 2 months?

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antonet
antonet 2012 年 8 月 17 日
Dear all
I have the following sequence of dates
A={
'24/09/2000'
'22/10/2000'
'19/11/2000'
'17/12/2000'
'14/01/2001'
'11/02/2001'
'11/03/2001'
'08/04/2001'
'03/06/2001'
'01/07/2001'
'29/07/2001'
'26/08/2001'
'23/09/2001'
'21/10/2001'}
I want to see if I have a jump of two months. for instance, in the above example there is such a jump from '08/04/2001' to '03/06/2001'.
I am looking for an if statement
if there is not such a jump
'...'
end
thanks

採用された回答

José-Luis
José-Luis 2012 年 8 月 17 日
編集済み: José-Luis 2012 年 8 月 17 日
Assuming your data is ordered, and that you have the financial toolbox:
numDate = datenum(A,'dd/mm/yyyy');
numDate = numDate - numDate(1);
monthNumber = month(test) + 12 * year(test);
jumpMonth = [0; diff(monthNumber)];
The vector jumpMonth will contain the difference in months between two succesive dates.
Cheers!

その他の回答 (2 件)

Wayne King
Wayne King 2012 年 8 月 17 日
The basic way to do it is using datenum()
B = datenum(A,'dd/mm/yyyy');
numdays = diff(B);
nummonths = numdays/30;
Then you need to use floor(), round(),ceil() or something similar, but you will see that only one element of nummonths is close to 2 in value
So, in this example
nummonths = ceil(nummonths);
for nn = 1:length(nummonths)
if (nummonths(nn) > 1.5 & nummonths(nn) < 3.5)
disp('There''s a jump');
else
disp('No Jump');
end
end
Anyway, you get the point.

Andrei Bobrov
Andrei Bobrov 2012 年 8 月 17 日
[m,m] = datevec(A,'dd/mm/yyyy');
test = [0;mod(diff(m),12)] == 2;

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