フィルターのクリア

How can I withdraw a colon operator from a string

1 回表示 (過去 30 日間)
Juan Rosado
Juan Rosado 2012 年 8 月 16 日
I have a colon operator within a string input (<1x30> char) that I would like to withdraw for later plotting.
The variable input is this:
WIND = NORTHEAST WINDS 8 : 13 KNOTS
I want just the characters
'8 : 13'
and make them operate as a colon operator. I was thinking of using a variation of 'find' command, but I don't know how to tell MATLAB to find colon operators within a text string.
Can you please help?

回答 (3 件)

Azzi Abdelmalek
Azzi Abdelmalek 2012 年 8 月 17 日
編集済み: Azzi Abdelmalek 2012 年 8 月 17 日
c1='WIND = NORTHEAST WINDS 8 : 13 KNOTS'
a=regexp(c1,'[0-9]')
result=c1(min(a):max(a))

Matt Kindig
Matt Kindig 2012 年 8 月 17 日
編集済み: Matt Kindig 2012 年 8 月 17 日
Mr. Azzi's technique is more general, and I would use it for your purpose.
However, if you did want to use 'find' to locate specific characters in a text string, you can do it simply as:
a = 'WIND = NORTHEAST WINDS 8 : 13 KNOTS'
location = find(a==':');

Matt Fig
Matt Fig 2012 年 8 月 17 日
編集済み: Matt Fig 2012 年 8 月 17 日
Here is another.
str = 'WIND = NORTHEAST WINDS 8 : 13 KNOTS'; % Example string
m = regexp(str,'\d+\s*:\s*\d+','match')
% Now to make it operate as a colon operator in an expression:
N = str2num(m{1})

カテゴリ

Help Center および File ExchangeNumeric Types についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by