How do I plot the bode plot of the transfer function with exp(sT)?
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The transfer function is show as following, where T=10e-9.
How could I get the bodeplot from this function?

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David Wilson
2019 年 5 月 6 日
Since you have the time delay element in the denominator, your don't have a polynomial transfer function anymore, so you will need to approximate it using pade.
You also might want to check that it is exp(-Ts), not the acausal version you have written above.
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Raj
2019 年 5 月 6 日
You can rearrange the equation as (e^-sT)(s+10)/s(1-(e^-sT))
Then your code should look something like this:
s = tf('s');
T=10e-9;
f = exp(-T*s);
sys=(f*(s+10))/(s*(1-f))
bode(sys)
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