How to solve a third order polynomial

I have the correct code to solving this question, but I was wondering why in line 2 there were the numbers 1,2,4,5? I do not understand why those specific numbers are there.
% Output a third-order polynomial function with the coefficients as the
% input variables
x = 0:10;
output = polynomial(x,1,2,4,5); % HELP HERE
% Convert the function to a function handle
poly_handle = @polynomial;
output2 = poly_handle(x,1,2,4,5);

1 件のコメント

Star Strider
Star Strider 2019 年 4 月 30 日
I cannot find a built-in function called ‘polynomial’ in the online documentation.
Are you asking about writing the function, or help on using it?

サインインしてコメントする。

回答 (0 件)

カテゴリ

ヘルプ センター および File ExchangePolynomials についてさらに検索

質問済み:

2019 年 4 月 30 日

コメント済み:

2019 年 4 月 30 日

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by