How to solve a third order polynomial
1 回表示 (過去 30 日間)
古いコメントを表示
I have the correct code to solving this question, but I was wondering why in line 2 there were the numbers 1,2,4,5? I do not understand why those specific numbers are there.
% Output a third-order polynomial function with the coefficients as the
% input variables
x = 0:10;
output = polynomial(x,1,2,4,5); % HELP HERE
% Convert the function to a function handle
poly_handle = @polynomial;
output2 = poly_handle(x,1,2,4,5);
1 件のコメント
Star Strider
2019 年 4 月 30 日
I cannot find a built-in function called ‘polynomial’ in the online documentation.
Are you asking about writing the function, or help on using it?
回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Polynomials についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!