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function coder.newtype not supported for code genertion

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Tamar Harpaz
Tamar Harpaz 2019 年 4 月 17 日
コメント済み: Ryan Livingston 2019 年 4 月 19 日
Hello friends,
Matlab coder asked me to make a input variable (for a function) as constant by using newtype.
After I did it, it says that the coder.newtype is not supported.

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回答 (1 件)

Ryan Livingston
Ryan Livingston 2019 年 4 月 17 日
Can you elaborate on where you used coder.newtype? If using the codegen command you can:
codegen myFunction -args {coder.typeof(1,[10,20],[0,1])}
To pass a constant input use:
codegen myFunction -args {coder.Constant(magic(3))}
Lastly, can you copy and paste the exact error message you're getting? It seems like something we could improve.

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Ryan Livingston
Ryan Livingston 2019 年 4 月 19 日
For coder.const to succeed, the input to it must be able to have a constant value computed for it. Look back through your code to find the variables that lead to the value of leftIR. Test each one of those with coder.const to find the root value which is non-constant.
Glancing over the code it looks like one of the dependencies leads to load. The output of load is never constant. You can instead try coder.load which always produces a constant value rather than load which is a runtime value.
Tamar Harpaz
Tamar Harpaz 2019 年 4 月 19 日
Thanks again.
I implemented your advice.
but a little problem for that 2 first lines:
hrtfDB= load ('ReferenceHRTF.mat');
The output of a call to 'load' is not assigned to a variable. Assign its output to a variable without subscripting when adding hrtfDB to the coder.const too.
Ryan Livingston
Ryan Livingston 2019 年 4 月 19 日
Rather than:
hrtfDB= load ('ReferenceHRTF.mat');
Try using:
hrtfDB = coder.load ('ReferenceHRTF.mat');
hrtfData = hrtfDB.hrtfData;







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