フィルターのクリア

problem with parfor in a subroutine

3 ビュー (過去 30 日間)
Luis Isaac
Luis Isaac 2019 年 4 月 9 日
コメント済み: Walter Roberson 2019 年 4 月 9 日
Dear;
I rather new using parfor computation.
The parfor execute a program in a parallel basis, when this program arrive to a routine:
function Erz=EFieldCalIdeal(r,z,V,RThimble,RCentral,LCentral)
for i=1:length(r)
...
if r(i)<=RThimble
28 Erz(i,1)=F/r(i);
elseif
...
end
end
end
Gives the following error:
Error using EFieldCalIdeal (line 28)
Assignment has more non-singleton rhs dimensions than non-singleton subscripts
But in fact, the program has no problem to run using a conventional for-loop.
Any idea?
Thanks a lot,
  3 件のコメント
Luis Isaac
Luis Isaac 2019 年 4 月 9 日
The parfor call the routine
Walter Roberson
Walter Roberson 2019 年 4 月 9 日
Is there any randomness involved inside the parfor ? And is there any solve() involved? How is F being constructed ?

サインインしてコメントする。

回答 (0 件)

カテゴリ

Help Center および File ExchangeLoops and Conditional Statements についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by