i am trying to find the euclidean distance of 2 vector with different sizes
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T =
5.1000 3.5000 1.4000 0.2000
6.4000 3.2000 4.5000 1.5000
5.4000 3.4000 1.7000 0.2000
5.7000 2.8000 4.5000 1.3000
5.7000 4.4000 1.5000 0.4000
5.6000 2.9000 3.6000 1.3000
X =
5.5000 3.8000 1.9000 0.4000
6.4000 2.9000 4.3000 1.3000
4.3000 3.0000 1.1000 0.1000
5.4000 3.0000 4.5000 1.5000
I want to use this method to find euclidean distance for each row of T and X in such a way use the each row of X to T(6,4)
for example first row will be = sqrt ((5.5 - 5.1)^2 + ((3.5 - 3.8)^2 + ((1.4 - 1.9)^2 + 0.2 -0.4)^2....................first row to the 24th row ( the number of row to obtain is 24)
Kindly get back to me thank
2 件のコメント
Adam
2019 年 4 月 8 日
The first row is clear enough, and up to the 4th row in your example posted above, but it's not clear what you are expecting where you have more rows in T than in X.
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Guillaume
2019 年 4 月 8 日
編集済み: Guillaume
2019 年 4 月 8 日
I'm also not clear on what you're asking. If you want to find the euclidean distance between each row of T and each row of X, then this is easily done:
T = [
5.1000 3.5000 1.4000 0.2000
6.4000 3.2000 4.5000 1.5000
5.4000 3.4000 1.7000 0.2000
5.7000 2.8000 4.5000 1.3000
5.7000 4.4000 1.5000 0.4000
5.6000 2.9000 3.6000 1.3000];
X = [
5.5000 3.8000 1.9000 0.4000
6.4000 2.9000 4.3000 1.3000
4.3000 3.0000 1.1000 0.1000
5.4000 3.0000 4.5000 1.5000];
distance = sqrt(sum((permute(T, [1 3 2]) - permute(X, [3 1 2])) .^ 2, 3))
distance(r, c) is then the distance between T(r, :) and X(c, :)
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