Select random elements from three consecutive columns in a big matrix?
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Hello all,
I have a 12 by 12 matrix, and I want to select 10 random elements. The elements should be from only three consecutive columns.
For example, I want to use 10 random elements from columns (1, 2, 3) or they could be from columns (2, 3, 4) or columns(3, 4, 5) and so on.
Any help please.
Thanks
3 件のコメント
Walter Roberson
2019 年 4 月 5 日
10 from each of the columns? 10 total from those 3 columns, with no effort to balance how many are to be taken from each individual column?
Please do not ask the same question twice.
Duplicate of https://www.mathworks.com/matlabcentral/answers/454534-select-elements-from-only-three-consecutive-columns
And it looks like you delete your question once answered, which is not going to go down well with us (and will be restored anyway).
AM-Laurentian
2019 年 4 月 5 日
回答 (2 件)
Walter Roberson
2019 年 4 月 5 日
N = 10;
[r, c] = size(YourMatrix);
start_col = randi([1, c-2]);
chosen = YourMatrix(start_col * r - 1 + randi([1 3*r], 1, N));
Jos (10584)
2019 年 4 月 5 日
編集済み: Jos (10584)
2019 年 4 月 5 日
M = magic(5) % input data
N = 4 % number of selections
nC = 3 % number of consecutive columns
% engine
szM = size(M)
r = randi(szM(1), N, nC) % N x 3 random rows
c = randi(szM(2) - nC + 1, N, 1) % N random first columns
c = c + [0:nC-1] % add consecutive columns
R = M(sub2ind(szM, r, c)) % index into M
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