Is there a way to combine number of matrices into one?

9 ビュー (過去 30 日間)
Moses Tang
Moses Tang 2019 年 4 月 4 日
コメント済み: Moses Tang 2019 年 4 月 4 日
Hi there, I would like to ask is there a way to join multiple matrices into a single one in a better way?
I was thinking maybe a for loop could do the job, but I don't know where to start as each data contains a different name.
For Example: Suppose I have 10 matrices, it is in the workspace as various name but equal sizes.
e.g) for all matrices in 10x10 size
matrix1_10
matrix11_20
matrix21_30.....
matrix91_100
I would like to join them into a column, so like 100x10 size matrix
I do know there is a way to do this.
If I would like to join each other vertically, well I could do [matrix1_10; matrix11_20 ; matrix21_30 ; ...... ; matrix91_100], it will do just fine.
However if the number of data was not 10 matrices, could be 1000, 10000 or more, what should I do in order to get the job done?
Like I said, probably a for loop may help me on this case. But I don't know what to begin with? Or is there a better solution to this?
Thank you.

採用された回答

Jan
Jan 2019 年 4 月 4 日
編集済み: Jan 2019 年 4 月 4 日
If you have 1000 arrays, it would be a really bad idea to store them in different variables, e.g. by hinding an index in the name of the variable. See TUTORIAL: Why and how to avoid Eval
If you use a cell array instead, the solution is trivial:
matrix = cell(1, 10);
for k = 1:10
matrix = cell(10, 10);
end
% Join the matrices vertically:
result = cat(1, matrix{:})
  1 件のコメント
Moses Tang
Moses Tang 2019 年 4 月 4 日
Thank you very much! I will consider this method and give it a try.

サインインしてコメントする。

その他の回答 (1 件)

Stephan
Stephan 2019 年 4 月 4 日
編集済み: Stephan 2019 年 4 月 4 日
Hi,
this solution is evil - since it uses eval:
A = whos;
A = {A.name};
B = string(ones(1,2*numel(A)-1));
B(2:2:end) = ",";
for k = 1:numel(A)
B(2*k-1) = A{k};
end
M = eval(join(['vertcat(',B,')']));
To use it make sure that only your variables are in workspace you want to join!
Example:
clear
M1 = zeros(3)
M2 = ones(3)
M3 = M1
M4 = randi(10,3)
results in
M1 =
0 0 0
0 0 0
0 0 0
M2 =
1 1 1
1 1 1
1 1 1
M3 =
0 0 0
0 0 0
0 0 0
M4 =
10 4 5
2 1 10
3 7 5
After running the script:
>> M
M =
0 0 0
0 0 0
0 0 0
1 1 1
1 1 1
1 1 1
0 0 0
0 0 0
0 0 0
10 4 5
2 1 10
3 7 5
But note that this is bad style - read here:
Best regards
Stephan
  1 件のコメント
Moses Tang
Moses Tang 2019 年 4 月 4 日
Although it's not the prefered method in joining the matrices, but thank you very much for your hardwork.
Thank you!

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeLogical についてさらに検索

タグ

製品


リリース

R2018b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by