How to convert an array of bytes to IEEE 754 single-precision float?

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Minh Tran
Minh Tran 2019 年 4 月 1 日
コメント済み: Minh Tran 2019 年 4 月 1 日
I'm using Matlab R2007b.
I have an array
[65 227 216 168]
which represents the hexadecimal digits
0x41E3D8A8
that I'd like to interpret as a single-precision IEEE 754 float. The value that float takes on should be approximately 28.4808.
I'm able to use several online calculators to convert 0x41E3D8A8 to ~28.4808 but I can't seem to get that value in Matlab, starting from the array representation of that Hex value. I tried:
single(typecast(uint8([65 227 216 168]), 'uint32')) % Returns 2.8328e+009

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採用された回答

James Tursa
James Tursa 2019 年 4 月 1 日
Try this:
>> swapbytes(typecast(uint8([65 227 216 168]),'single'))
ans =
single
28.4808

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