Partial Differential Equation Toolbox
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Help please, I need to solve this differential equation in Matlab (where "a" is a constant parameter, it can be taken by any), I wanted to use the Partial Differential Equation Toolbox, but I ran into a problem, the elliptic equation in this Toolbox is represented in a vector form, namely -div(c*grad(u))+a*u=f.
Please help me convert my equation to this form and tell me how it can be done or at least name the sources of information from which I can learn this knowledge.
I really need to solve this equation in Matlab,so please tell me how it can be done.
2 件のコメント
Torsten
2019 年 4 月 1 日
What is the domain where you want to solve the equation and what are the boundary and initial conditions ?
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Torsten
2019 年 4 月 2 日
編集済み: Torsten
2019 年 4 月 2 日
Take
c = [- x, x - y ; - ( x - y ), - y]
Then
-div(c*grad(u)) = x * d^2u/dx^2 + y * d^2u/dy^2
Section 2-62 in
http://www.cmap.polytechnique.fr/~jingrebeccali/frenchvietnammaster2_files/2017/pdetool_doc
2 件のコメント
Bosnian Kingdom
2019 年 6 月 2 日
Can you put you code here or can you send me on e-mail or private message? I really need example of pde solution.
Thanks in advance.
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