Convert C++ Code to Matlab Code with MATLAB 2019a

I have large files that I would like to convert from C++ to Matlab code. Previous responses on MATLAB Answers indicate that this must be done manually, but is this still the case for the most recent version of MATLAB?

Answer 1

[David Fink]

If your overall goal is to convert C++ code to MATLAB code, yes, manual conversion is still required in R2019a.

However, if you only need to call the C++ code from MATLAB, simpler solutions are possible (in older releases as well as R2019a):

Option A: create a MEX file via MATLAB Coder (using MATLAB Coder on a simple M file that just calls the C++ function using coder.cinclude and coder.ceval) - see the last comment on a similar question.

Option B: create a MEX file via the MEX command (you will need to write a MEX wrapper for the C++ code). More information can be found on this documentation page.

Answer 2

[Venkatesh Khemlapure]

#include <iostream>
using namespace std;


int getMax(int arr[], int n)
{
	int mx = arr[0];
	for (int i = 1; i < n; i++)
		if (arr[i] > mx)
			mx = arr[i];
	return mx;
}

void countSort(int arr[], int n, int exp)
{
	int output[n]; 
	int i, count[10] = { 0 };


	for (i = 0; i < n; i++)
		count[(arr[i] / exp) % 10]++;


	for (i = 1; i < 10; i++)
		count[i] += count[i - 1];

	for (i = n - 1; i >= 0; i--) {
		output[count[(arr[i] / exp) % 10] - 1] = arr[i];
		count[(arr[i] / exp) % 10]--;
	}

	for (i = 0; i < n; i++)
		arr[i] = output[i];
}

void radixsort(int arr[], int n)
{
	int m = getMax(arr, n);


	for (int exp = 1; m / exp > 0; exp *= 10)
		countSort(arr, n, exp);
}

void print(int arr[], int n)
{
	for (int i = 0; i < n; i++)
		cout << arr[i] << " ";
}

int main()
{
	int arr[] = { 170, 45, 75, 90, 802, 24, 2, 66 };
	int n = sizeof(arr) / sizeof(arr[0]);

	radixsort(arr, n);
	print(arr, n);
	return 0;
}

Answer 3

[Asad]

#include <stdio.h>


int main(int argc, char const *argv[])
{
    
int M1x, M1y, M2x, M2y;

printf("Enter Matrix 1 x and y with a space in between: ");
scanf("%d %d", &M1x, &M1y);
printf("Enter Matrix 2 x and y with a space in between: ");
scanf("%d %d", &M2x, &M2y);

int M1[M1x][M1y];
int M2[M2x][M2y];
int MatOut[50][50];

for (int x1 = 0; x1 < M1x; x1++)
    {
        for (int y1 = 0; y1 < M1y; y1++)
        {
            printf("Enter Matrix 1[%d][%d]: ", x1 + 1, y1 + 1);
            scanf("%d", &M1[x1][y1]);
            }
        }
        printf("\nMatrix 1 is:\n");
        for (int x1 = 0; x1 < M1x; x1++)
            {
                for (int y1 = 0; y1 < M1y; y1++)
                {
                    printf("%d ", M1[x1][y1]);
                    }
                printf("\n");
                }
                printf("\n");
                
                for (int x2 = 0; x2 < M2x; x2++)
                    {
                        for (int y2 = 0; y2 < M2y; y2++)
                        {
                            printf("Enter Matrix 2[%d][%d]: ", x2 + 1, y2 + 1);
                            scanf("%d", &M2[x2][y2]);
                            }
                        }
                        printf("\nMatrix 2 is:\n");
                        for (int x2 = 0; x2 < M2x; x2++)
                            {
                                for (int y2 = 0; y2 < M2y; y2++)
                                {
                                    printf("%d ", M2[x2][y2]);
                                    }
                                printf("\n");
                                }
                                printf("\n");
                                
                                
                                
                                return 0;
                                }

[Walter Roberson]

for

fprintf

input

sprintf

zeros

Answer 4

[Radu-Andrei]

#include<iostream.h>
using namespace std;
int main()
{
int a;
do
{
    cout<<"Dati un numar strict pozitiv, a=";
    cin>>a;
}
while(a<=0);
cout<<"Avem a="<<a<<endl;
system("pause");
}

[Walter Roberson]

a = fix(input("Dati un numar strict pozitiv, a="));

fprintf("Avem a=%d\n", a);