invalid syntax at '=' . A '(' might be missing a closing ')'

2 ビュー (過去 30 日間)
valerio auricchio
valerio auricchio 2019 年 3 月 29 日
コメント済み: Guillaume 2019 年 3 月 29 日
The error is at line 14 and 26
switch nargin
case 0
disp('Non ci sono stati input per la funzione!')
case 1
if (f = 0)
disp('Non hai inserito correttamente la funzione la funzione')
end
case 2
if(~isscalar(xo) || isinteger(xo))
disp('Mammt')
end
case 3
if(~isscalar(xo) || isinteger(xo)) % anche se ci sta un altro controllo che nello non vuole dirmi
disp('A')
end
case 4
if(~isinteger(NMAX) || NMAX = 0 || ischar(NMAX))
disp('A pecrrrr, cioè nmax non va bene')
end
end

採用された回答

Catalytic
Catalytic 2019 年 3 月 29 日
編集済み: Catalytic 2019 年 3 月 29 日
if (f == 0)
and same thing in this line
if(~isinteger(NMAX) || NMAX == 0 || ischar(NMAX))
  1 件のコメント
Guillaume
Guillaume 2019 年 3 月 29 日
Note that matlab is not C, there is no need to enclose a conditional statement in (), so
if f == 0
if ~isinteger(NMAX) || NMAX == 0 || ischar(NMAX)
Note that isinteger check that the type is integer not that the values are integer,
>> isinteger(1) %return false, since double is not an integer type
ans =
logical
0
>> isinteger(uint8(1)) %return true, the type is integer
ans =
logical
1
I suspect that you meant to test if the value was integer, not the type.
Also note that the ischar(NMAX) is redundant, if NMAX is char, it will have failed the ~isinteger test.
You may want to use validateattributes instead of writing your own tests:
validateattributes(f, {'numeric'}, {'nonzero', 'scalar'});
validateattributes(NMAX, {'numeric'}, {'integer', 'nonzero', 'scalar'})

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeLogical についてさらに検索

製品


リリース

R2018b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by