Solving for a variable with varying parameters in the sum

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Jigsaw
Jigsaw 2019 年 3 月 21 日
コメント済み: Jigsaw 2019 年 3 月 22 日
being the unknown variable, how to initialize and write the following equation in matlab script containing varying paramters.
(n = 0,1,2,...)
  2 件のコメント
Kevin Phung
Kevin Phung 2019 年 3 月 21 日
What have you tried?
Jigsaw
Jigsaw 2019 年 3 月 22 日
@Kevin
Tried implementing using symbolic variables. It gets complicated and confusing considering the summation and varying m as well as n values.

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Walter Roberson
Walter Roberson 2019 年 3 月 21 日
You cannot. That describes an infinite summation where you need to solve all infinite I_m values.
You cannot truncate it because truncation would imply that if you were to make some I_m indefinitely big for some "large" m, that it would not make a substantial difference to the summation -- but clearly if you know the a_m c_m_n R_m_n values then you can create a corresponding I_m value that overwhelms any previous sum you might have had.
  3 件のコメント
Jigsaw
Jigsaw 2019 年 3 月 22 日
@Walter:
What about if instead of a finite number was used, like so:
(n = 0,1,2,...)
As or your second comment, , and have known relations but contain varying parameters too. For example \alpha_m from the above equation = , where π and a are known constants.
Torsten
Torsten 2019 年 3 月 22 日
How do you intend to exclude the trivial solution I_m = 0 for all m ?

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