Design Matrix set up
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I am creating a desgin matrix for a data set and I have this equation
y(t)=a1 + a2 exp(-(t-0.0001)/50^2) + a3 sin(2π(60)t)
When I am entering it into matlab I keep getting error and I don't know what I am doing wrong.
Code:
X=(2*pi*(60)*t);
A = [ones(length(t),1) exp(-((t-0.0001)/50).^2)' sin(2*pi*(60)*t)];
Output:
Error using horzcat
Dimensions of arrays being concatenated are not consistent.
4 件のコメント
Mark Sherstan
2019 年 3 月 21 日
Try running it again as so:
clear all
t = 5;
X=(2*pi*(60)*t);
A = [ones(length(t),1) exp(-((t-0.0001)/50).^2)' sin(2*pi*(60)*t)];
I dont see any issues so perhaps you have over written some variable somehwere or is t an array / vector of values?
Walter Roberson
2019 年 3 月 21 日
The code assumes that t is a column vector and will fail if it is a row vector.
Emilee Burris
2019 年 3 月 23 日
Walter Roberson
2019 年 3 月 23 日
Before the assignment to X, insert
t = t(:);
That should fix the problem.
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