Generate random number from a two-parameter exponential distribution

Hello everybody,
I am looking for a way to easily generate random numbers from a two-parameter exponential distribution. The probability density function is: . I am aware of expand() but it does not seem to include the two-parameter distribution.
Do you have any idea how I could achieve that?
Thank you very much.
Alexis

4 件のコメント

Torsten
Torsten 2019 年 3 月 21 日
Your function f does not depend on t ?
Alexis Stevenson
Alexis Stevenson 2019 年 3 月 21 日
Sorry typo :) Thank you for noticing it.
Torsten
Torsten 2019 年 3 月 21 日
What is the support of f ?
I ask because if support(f) = IR+, f is only a probability density function if gamma = 0.
Alexis Stevenson
Alexis Stevenson 2019 年 3 月 21 日

サインインしてコメントする。

 採用された回答

Torsten
Torsten 2019 年 3 月 21 日

0 投票

gam = ...;
lambda = ...;
n = 100;
x = gam - log(1-rand(n,1))/lambda
give you 100 random numbers distributed according to your two-parameter distribution.

1 件のコメント

Alexis Stevenson
Alexis Stevenson 2019 年 3 月 21 日
編集済み: Alexis Stevenson 2019 年 3 月 21 日
Oh yes thank you so much !
I just realized the cdf was and I had to invert it.

サインインしてコメントする。

その他の回答 (0 件)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by