How to replace 2x2 zero sub matrices by different 2x2 matrices ?
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How to replace 2x2 zero submatrix of B with 2x2 matrices different matrice.I have 12 matrices of size 2x2 and want to replace zeros of B by those matrices.
B =
0.8776 0.6513 0 0 0 0 0 0
0.0144 0.8646 0 0 0 0 0 0
0 0 0.2943 0.0560 0 0 0 0
0 0 0.1799 0.8169 0 0 0 0
0 0 0 0 0.9263 0.5289 0 0
0 0 0 0 0.0682 0.6944 0 0
0 0 0 0 0 0 0.5811 0.2124
0 0 0 0 0 0 0.6372 0.5433
Thanks
8 件のコメント
Guillaume
2019 年 3 月 18 日
The loop would imply that you want to create 12 matrices. However, since it overwrites the matrices in the previous step, you'll end up with only 3 matrices. The ones created on the last step of the loop.
While you say that you have 12 matrices, your I want solution in this form implies that there are only 3 matrices, which are rotated on each row.
A bit confusing as to what you have.
I doubt it will be difficult to do what you want, but the method will vary depending on exactly what it is that you want. So, please clarify.
採用された回答
Matt J
2019 年 3 月 18 日
編集済み: Matt J
2019 年 3 月 18 日
basically i want solution in this form
x p1 p2 p3
p1 x p2 p3
p1 p2 x p3
p1 p2 p3 x
C={zeros(2), p1,p2,p3};
result=B+cell2mat( C(toeplitz(1:4)) );
3 件のコメント
Matt J
2019 年 3 月 18 日
Very similar to things I've already mentioned:
B(B==0)=cat(3,matrix4,matrix7,matrix10,matrix1,matrix8,matrix11,...
matrix2,matrix5,matrix12,matrix3,matrix6,matrix9);
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