Index into array out of range error in simulink
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Runtime error: Index into array out of range
Model Name: simm_1
Block Name: simm_1/MATLAB Function
Attempted to access 2 element of data a. The valid index range is 1 to 1
Please note that the simulation will be aborted immediately after you continue from this breakpoint to avoid segmentation violations.
I am a beginner in simulink.Please help me to fix this error . I have attached my simulink model and matlab function
function p1=simm(p)
cp=1;
cp1=5;
a=0.3;
a1=0.4;
b=0.2;
b1=0.4;
for i=1:50
a(i+1)= cp*sin(pi*a1(i))*sin(cp1/a(i));
a1(i+1)= cp*sin(pi*a(i+1))*sin(cp1/a1(i));
end
for i=1:128
a(i+1)= cp*sin(pi*a1(i))*sin(cp1/a(i));
a1(i+1)= cp*sin(pi*a(i+1))*sin(cp1/a1(i));
end
a=a(2:129);
a1=a1(2:129);
for i=1:50
b(i+1)= cp*sin(pi*b1(i))*sin(cp1/b(i));
b1(i+1)= cp*sin(pi*b(i+1))*sin(cp1/b1(i));
end
for i=1:128
b(i+1)= cp*sin(pi*b1(i))*sin(cp1/b(i));
b1(i+1)= cp*sin(pi*b(i+1))*sin(cp1/b1(i));
end
b=b(2:129);
b1=b1(2:129);
N=128;
R=N-1;
for i=1:128
k1=uint8(mod(floor(a*power(10,5)),255)+1);
k2=mod(floor(a1*power(10,5)),R)+1;
p(i,:)=bitxor(p(i,:),k1);
p(i,:)=circshift(p(i,:),[0 k2(i)]);
end
N=128;
R=N-1;
for i=1:128
k1=uint8(mod(floor(a*power(10,5)),255)+1);
k2=mod(floor(a1*power(10,5)),R)+1;
p(:,i)=bitxor(p(:,i),k1');
p(:,i)=circshift(p(:,i),[-k2(i) 0]);
end
N=128;
R=N-1;
for i=1:128
k1=uint8(mod(floor(b*power(10,5)),255)+1);
k2=mod(floor(b1*power(10,5)),R)+1;
p(i,:)=bitxor(p(i,:),k1);
p(i,:)=circshift(p(i,:),[0 k2(i)]);
end
N=128;
R=N-1;
for i=1:128
k1=uint8(mod(floor(b*power(10,5)),255)+1);
k2=mod(floor(b1*power(10,5)),R)+1;
p(:,i)=bitxor(p(:,i),k1');
p(:,i)=circshift(p(:,i),[-k2(i) 0]);
end
p1=p;
end
回答 (1 件)
Rajanya
2025 年 5 月 13 日
MATLAB Function Blocks always need to be compatible for code generation but the code provided above has growing arrays which are not supported in the way they are used. It, therefore, fails at this line itself-
a(i+1)= cp*sin(pi*a1(i))*sin(cp1/a(i)); % Growing array 'a'
Currently, Code Generation only supports growing arrays when used with 'end+1' indexing - as mentioned here.
Thanks!
1 件のコメント
Walter Roberson
2025 年 5 月 13 日
Huh, I did not know that could be done !
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