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How to modify this could so it can read from different files groups?

Ismail Qeshta さんによって質問されました 2019 年 2 月 20 日
最新アクティビティ Ismail Qeshta さんによって コメントされました 2019 年 2 月 21 日
Hi,
I have this code that reads from 10 files each maximum X value and its corresponding Y value and prints all results in one file (named "Result_1, Result_2,...")
Now, I have 400 files. I need to modify the code, so it can read the different groups sequentially and print the output file for each group.
For instance, I need it to read from 1 to 10, then from 11 to 20, then from 21 to 30, and so on until 391 to 400.
Hence, the printed output files are: Result_1 (for files 1 to 10), Result_2 (for files 11 to 20), and so on until the output file Result_40 (for files 391 to 400).
The code:
S = dir('*.out');
C = natsortfiles({S.name});
N = numel(C);
Z = nan(N,1);
for k = 1:N
data = load(C{k});
[~,idx] = max(data(:,1));
Z(k) = data(idx,2);
end
dlmwrite('Result_1.txt',Z)

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1 件の回答

回答者: Bob Nbob
2019 年 2 月 20 日
 採用された回答

Add a second loop. Instead of just going through all files in a single loop, have an outer loop that looks for the number of groups you have, and an inner loop that has the number of files in each group. The example below assumes you have a constant number of files in each group.
S = dir('*.out');
C = natsortfiles({S.name});
N = numel(C);
g = 10;
Z = nan(g,1);
for k = 1:N/g
for j = 1:g;
data = load(C{10*(k-1)+j});
[~,idx] = max(data(:,1));
Z(j) = data(idx,2);
end
dlmwrite(['Result_',num2str(k),'.txt'],Z);
end

  10 件のコメント

I see. So, g refers to the file groups to be read and printed in each output file, is that correct?
g refers to the number of sets of data to be printed into each output. So, I think we are saying the same thing, yes.
Thank you very much Bob for all your time and help.

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