Sub-scripting a table

2 ビュー (過去 30 日間)
Lui
Lui 2019 年 2 月 19 日
コメント済み: Lui 2019 年 2 月 20 日
Hi everyone,
I have an 8928x41 table with datetime values in the first column. I am trying to group the values in this table according to time.
I have done this with a similar table to retrieve data for particular monthsa and yeasr as below:
T1=T(2010==year(T.Date),:); % Retrieves the data for the year 2010
T2=T(7==month(T.Date),;); % retrieves the data for July
I assume that if I do the same thing for the hour, it will yield the results but below is a sample of the results I got from the data set
hour20=MarchData(20==hour(MarchData.Date),:);
sample.PNG
How can I get data for hour 20 (20:00) alone?
Secondly Can someone help me write an iteration to do this for the 24 hours in a day?
Thank you.
  1 件のコメント
Peter Perkins
Peter Perkins 2019 年 2 月 20 日
It's not really clear what you are asking. If you want the one row for 8pm on that day, you aren't grouping anything. And it's not clear what you want to do with the groups of data.
In any case, it usually true that you don't need to explicitly separate the data into groups. Things like varfun, groupsummary, and splitapply are happy to work across all groups for you.
Consider puttig your data in a timetable, and using retime with one of the aggregation syntaxes to reduce your data to hourly values, if that's what you are trying to do.

サインインしてコメントする。

採用された回答

per isakson
per isakson 2019 年 2 月 20 日
編集済み: per isakson 2019 年 2 月 20 日
Try and replace
hour20=MarchData(20==hour(MarchData.Date),:);
by
clock2000 = MarchData((hour(MarchData.Date)==20 & minute(MarchData.Date)==0),:);
  1 件のコメント
Lui
Lui 2019 年 2 月 20 日
Thank you. This worked

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeTimetables についてさらに検索

タグ

製品


リリース

R2018a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by