フィルターのクリア

Laplace inversion for fractional-order transfer functions

4 ビュー (過去 30 日間)
Ehsan Khorsandnejad
Ehsan Khorsandnejad 2019 年 2 月 11 日
回答済み: Patel Mounika 2019 年 2 月 20 日
I am using the FOMCON toolbox, which enables me to introduce transfer functions with a fractional order. However, when I want to use the laplace inversion function, it works for simple cases but not for a bit complicated equations. Can anyone help me with this?
Example 1: works
syms s
TF = 1/s^0.5;
ilaplace(TF)
ans =
1/(t^(1/2)*pi^(1/2))
Example 2: does not work (only works when a = integer)
syms s
a = 0.5
TF = 1/(5 + (3*(s^a + (1/2^a)))/(s^a + (1/6^a)));
ilaplace(TF)
answ =
ilaplace(1/(((3*2^(1/2))/2 + 3*s^(1/2))/(6^(1/2)/6 + s^(1/2)) + 5), s, t)

採用された回答

Patel Mounika
Patel Mounika 2019 年 2 月 20 日
The ilaplace function of the symbolic engine currently does not implement an explicit expression for
ilaplace(1/(5 + (3*(s^a + (1/2^a)))/(s^a + (1/6^a)))) if a is not an integer .
The ilaplace function computes the analytic closed inverse Laplace form of a transfer function. It seems that mathematically a closed inverse Laplace form for 1/(5 + (3*(s^a + (1/2^a)))/(s^a + (1/6^a))) for general a cannot be found out, so ilaplace function will not simplify it further.
Nevertheless, there is a community submission at MathWorks File Exchange which numerically approximates an inverse Laplace transform for any function of "s". Following is the link of the same:

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeCalculus についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by