How to convert dependent equation to independent for parallel computing (parfor)

1 回表示 (過去 30 日間)
Abhishek Saini
Abhishek Saini 2019 年 2 月 11 日
コメント済み: Walter Roberson 2019 年 2 月 11 日
I am trying to run my code using 'parfor' but getting error due to dependent term. How to resolve that.
The code similar to below. I am getting error for third loop expression
image(: , : , i) = image(: , : , i) + image(: , : , i -1);
parfor ix = 1:nx
% expression to calculate image_c and image_d
for i = 1:nt
image(:,:,i) = image_c(:,:,i) +image_d(:,:,i);
end
for i=2:nt
image(:,:,i) = image(:,:,i) +image(:,:,i-1);
end
end

回答 (1 件)

Walter Roberson
Walter Roberson 2019 年 2 月 11 日
You cannot do that in parallel.
What you can do is roughly
total = zeros(size(image));
parfor i = 1 : nt
total = total + image(:,:,i);
end
MATLAB recognizes total as being a "reduction variable" and will take care of doing the relevant additions and locking.
  5 件のコメント
Walter Roberson
Walter Roberson 2019 年 2 月 11 日
why bother to take a cumulative sum of snapshot_i but then only extract the last layer? Why not just sum(snapshot_i,3) ?
Walter Roberson
Walter Roberson 2019 年 2 月 11 日
Also it looks like
snapshot_i = snapshot_c .* snapshot_d;
with no loop needed ?

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeLoops and Conditional Statements についてさらに検索

製品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by