In need of decreasing exponential smooth curve
2 ビュー (過去 30 日間)
古いコメントを表示
u=0.3; pi=22/7; g=80;
l=20; d=10; p=1;
r=linspace(0,1,10);
m=tand(p)
a=(r-m*(d+l)).^-2-((r-m*l).^-2)
q=(pi*r.^4*g)/(8*u*l)
t=(2*u*q.*a)/(pi*m)
plot(r,t)
I need a decreasing smooth exponential curve. please help me
0 件のコメント
採用された回答
Stephan
2019 年 2 月 10 日
編集済み: Stephan
2019 年 2 月 10 日
Your linspace call will lead to 10 results calculated in the interval of 0...1. If you leave the 10 away, the standard is 100 values, which gives a smoother curve:
u=0.3; g=80;
l=20; d=10; p=1;
r=linspace(0,1);
m=tan(p);
a=(r-m*(d+l)).^-2-((r-m*l).^-2);
q=(pi*r.^4*g)/(8*u*l);
t=(2*u*q.*a)/(pi*m);
plot(r,t)
You should also do not overwrite pi - it is a constant in Matlab - no need to define it.
Best regards
Stephan
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Smoothing についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!