How to linearly change values in matrix
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Observe this matrix:
thismatrix = eye(5)
thismatrix =
1 0 0 0 0
0 1 0 0 0
0 0 1 0 0
0 0 0 1 0
0 0 0 0 1
I wish to replace the zeros on either size of the 1's on every row with values descending from 1 by 0.1.
This is what I want:
thismatrix =
1.0000 0.9000 0.8000 0.7000 0.6000
0.9000 1.0000 0.9000 0.8000 0.7000
0.8000 0.9000 1.0000 0.9000 0.8000
0.7000 0.8000 0.9000 1.0000 0.9000
0.6000 0.7000 0.8000 0.9000 1.0000
How can I accomplish this without numerous "for loops"/spaghetti code (especially if my matrix is larger)?
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採用された回答
Andrei Bobrov
2019 年 1 月 28 日
編集済み: Andrei Bobrov
2019 年 1 月 28 日
toeplitz(1:-.1:.6)
or
1 - abs((1:5) - (1:5)')*.1
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