question using while loop
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variable = input('Continue?', 's');
while variable == 'y'
disp(rand)
variable = input('Continue?', 's');
if (variable ~= 'y')
return
end
end
Need to write a code that if you type 'y', it displays a random variable. If the typed variable is not equal to 'y' then the program should terminate. When I run my code, it keeps displaying "continue?" no matter what variable I type. How would I get this to display a number? (needs to use a while loop)
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回答 (1 件)
Stephen23
2019 年 1 月 23 日
編集済み: Stephen23
2019 年 1 月 23 日
v = input('Continue?', 's');
while strcmpi(v,'y')
disp(rand)
v = input('Continue?', 's');
end
When applied to character vectors the equivalence operator == performs an element-wise comparison (as it does on all array types). To compare the complete character vector, use strcmp or strcmpi.
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