How can plot multiple same amplitude signals along with same y axis ?

1 回表示 (過去 30 日間)
Zara Khan
Zara Khan 2019 年 1 月 22 日
コメント済み: Star Strider 2019 年 2 月 2 日
I am using this code to plot multiple signals. But unable to plot using same y axis. I am some overlapping plot due same amplitude. How to manage them in same figure? Signals will be in dufferent length but later I want to scale them with same length. I am attaching figure that is representing how will be my output.
clc;
close all;
clear;
workspace;
a = imread('img.png');
bwimg =bwareafilt(~a, 1);
s=regionprops(bwimg,'Orientation','Centroid','MajorAxisLength','MinorAxisLength');
circleCenterX =s.Centroid(1);
circleCenterY =s.Centroid(2);
diameters = mean([s.MajorAxisLength s.MinorAxisLength],2);
t=0:0.001:2*pi;
r1 =1*diameters/8;
x = circleCenterX + r1 * sin(t);
y = circleCenterY + r1 * cos(t);
[r,c]=size(bwimg);
bw=false(r,c);
t=0:0.001:2*pi;
bw =bw|poly2mask(x,y,r,c);
boundaries = bwboundaries(bw);
thisBoundary = boundaries{1};
x1=thisBoundary(:,2);
y1=thisBoundary(:,1);
indexes = y1<circleCenterY; % Only those in the upper half.
xTop = x1(indexes);
yTop = y1(indexes);
figure;
for k=1:length(xTop )
profile(k) = bwimg(yTop(k),xTop(k ));
plot(profile,'r-','LineWidth',2 );
%grid on ;
ylim([0 2]);
axis off;
end
r2 =2*diameters/8;
x2 = circleCenterX + r2 * sin(t);
y2 = circleCenterY + r2 * cos(t);
bw =bw|poly2mask(x2,y2,r,c);
boundaries = bwboundaries(bw);
thisBoundary = boundaries{1};
x3=thisBoundary(:,2);
y3=thisBoundary(:,1);
indexes = y3<circleCenterY; % Only those in the upper half.
xTop1 = x3(indexes);
yTop1= y3(indexes);
for k=1:length(xTop1)
profile1(k) = bwimg(yTop1(k),xTop1(k ));
plot(profile1,'b-','LineWidth',2 );
%grid on ;
ylim([0 2]);
axis off;
end
r3 =7*diameters/8;
x4= circleCenterX + r3 * sin(t);
y4= circleCenterY + r3 * cos(t);
bw =bw|poly2mask(x4,y4,r,c);
boundaries = bwboundaries(bw);
thisBoundary = boundaries{1};
x5=thisBoundary(:,2);
y5=thisBoundary(:,1);
indexes = y5<circleCenterY; % Only those in the upper half.
xTop2 = x5(indexes);
yTop2 = y5(indexes);
for k=1:length(xTop2)
profile2(k) = bwimg(yTop2(k),xTop2(k ));
plot(profile2,'r-','LineWidth',2 );
%grid on ;
ylim([0 2]);
axis off;
end
r4 =8*diameters/8;
x5= circleCenterX + r4 * sin(t);
y5= circleCenterY + r4 * cos(t);
bw =bw|poly2mask(x5,y5,r,c);
boundaries = bwboundaries(bw);
thisBoundary = boundaries{1};
x6=thisBoundary(:,2);
y6=thisBoundary(:,1);
indexes = y6<circleCenterY; % Only those in the upper half.
xTop3 = x6(indexes);
yTop3 = y6(indexes);
for k=1:length(xTop3)
profile3(k) = bwimg(yTop3(k),xTop3(k ));
plot(profile3,'b-','LineWidth',2 );
%grid on ;
ylim([0 2]);
axis off;
end
  4 件のコメント
Zara Khan
Zara Khan 2019 年 1 月 22 日
I have attached a picture to explain what type of output I am expecting
Jan
Jan 2019 年 1 月 22 日
I do not get any idea, how the attached images concern the described problem. You have posted a pile of code, but it is not clear, which lines are interesting to understand, what you want to achieve. Does "cant separate all the signals" mean, that you want to separate some signals? Please elaborate this again. I know, that it is hard to do this in a foreign language, but don't give up. Explain the problem, until somebody understands it and support you to find a solution.

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採用された回答

Star Strider
Star Strider 2019 年 1 月 22 日
編集済み: Star Strider 2019 年 1 月 22 日
Try something like this using the bsxfun (link) function:
x = linspace(0, 2*pi); % Independent Variable
y = sin((0:5)'*x); % Original Signals
y = bsxfun(@plus, y, (0:size(y,1)-1)'*2); % Separated Signals
figure
plot(x, y)
grid
EDIT —
Added plot:
How can plot multiple same amplitude signals along with same y axis - 2019 01 22.png
  21 件のコメント
Zara Khan
Zara Khan 2019 年 1 月 23 日
'Profiles' are not in same length.
Star Strider
Star Strider 2019 年 1 月 23 日
Then just do something like this:
profile_a = profile;
profile1_a = profile1 + 2;
prodile2_a = profile2 + 4;
profile3_a = profile3 + 6;
Then plot ‘profile_a’ and the others, instead.

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その他の回答 (1 件)

Zara Khan
Zara Khan 2019 年 2 月 2 日
Star Strider : Thank you. finally I am done with this. its working well.

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