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Initialization of array of structure

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Thulasi Durai Durai Samy
Thulasi Durai Durai Samy 2012 年 7 月 19 日
Hello
I have a created array of structure (named LD) which incrementes from 1 to no of database (eg LD(1) to LD(10)). The structure has some fields. After some time I need to re-initialise the structure.
I tried with following commands.
LD = [];
But, I lost the field names, how to initialise with out loosing the field names.

採用された回答

Walter Roberson
Walter Roberson 2012 年 7 月 19 日
Experiment with
LD = LD(false);
  4 件のコメント
Walter Roberson
Walter Roberson 2012 年 7 月 20 日
Yes, that is fine.
Walter Roberson
Walter Roberson 2012 年 7 月 20 日
For the clearing, you might be able to use
LD(:) = [];
Unfortunately I cannot test that at the moment.

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その他の回答 (2 件)

Nirmal
Nirmal 2012 年 7 月 19 日
You shouldnt do LD=[], instead you should change the field of each of the structure in the array.

Conrad
Conrad 2012 年 7 月 19 日
The following code should do the trick:
function is = StructInit(s)
is = s;
if isstruct(s)
f = fields(s);
for i = 1 : length(f);
if isstruct(is.(f{i}))
is.(f{i}) = StructInit(is.(f{i}));
else
is.(f{i}) = [];
end
end
else
is = [];
end
end
Here is an example how to use it:
% Create dummy structure.
a.a = 1;
a.b = '';
a.c = {};
a.d.a.a = 2;
a.d.a.b = 1;
a.d.b = {};
initialisedStruct = StructInit(a);
All the fields are initialised to []. If a field is a structure, that structure's fields will be initialised etc.
Conrad

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