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Matlab stuck at Warning about Integers
4 ビュー (過去 30 日間)
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Hi people,
I need help. I'm running a code and I am getting stuck at line 51 that reads:
sortedData = sort(cutData(tstart:tend));
baseline = median(sortedData(1:((0.2)*length(cutData(tstart:tend)))));
deltaF(i) = (cutData(i) - baseline)/baseline;
This is the message I keep getting:
> In scrapAnalysis (line 51)
Warning: Integer operands are required for colon operator when used as index
1 件のコメント
Walter Roberson
2019 年 1 月 16 日
length(cutData(tstart:tend) is going to be the same as tend-tstart+1 . But suppose that does not happen to be an exact multiple of 5, so 0.2 times the value does not turn out to be an integer?
回答 (3 件)
Fangjun Jiang
2019 年 1 月 16 日
With this, do you get it?
>> a=rand(1,100);
>> b=a(2:10);
>> c=a(2:0.9:10);
Warning: Integer operands are required for colon operator when used as index.
0 件のコメント
Star Strider
2019 年 1 月 16 日
Without knowing more about ‘cutData’, it’s difficult to provide a specific solution. Subscripts must be integers greater than 0, or logicals
Assuming that ‘t’ is your time vector associated with ‘cutData’, try this:
tstart = ...;
tend = ...;
idx1 = find(t >= tstart, 1, 'first');
idx2 = find(t <= tend, 1, 'last');
sortedData = sort(cutData(idx1:idx2));
Something like that should do what you want. You will have to experiment with it with your code.
0 件のコメント
Mark Dawnson
2019 年 1 月 17 日
1 件のコメント
Star Strider
2019 年 1 月 17 日
It would also help to know the complete error message. (Please copy all the red text in your Command Window and paste it to a Comment here).
There are at least two lines that could be throwing that error. We have no idea which one it is.
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