Crossover applications in matlab

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Johan Johan
Johan Johan 2019 年 1 月 6 日
コメント済み: Walter Roberson 2019 年 1 月 7 日
I want to apply crossover betweem x1 and x2
x1=[ -1.0000 - 1.0000i 2.0000 - 2.0000i 3.0000 - 3.0000i];
x2=[ -4.0000 - 4.0000i 5.0000 - 5.0000i 6.0000 - 6.0000i];
CrossoverIndex=1;
>> c2 = [x2(1:CrossoverIndex) x1(CrossoverIndex+1:end)];
But i found this error:
Error using horzcat
Dimensions of matrices being concatenated are not consistent.
Can any one help me how can i solve the error.

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Walter Roberson
Walter Roberson 2019 年 1 月 7 日
you show x1 and x2 as row vectors but your code is p1 and p2. If p1 and p2 are column vectors you would have problems with your [] operation if the crossover was not exactly half way . II suspect you should use ; between the parts.
  4 件のコメント
Johan Johan
Johan Johan 2019 年 1 月 7 日
Thank you very much, the problem is solved if using the transpose operation :
c2 = [x2(1:CrossoverIndex)' x1(CrossoverIndex+1:end)'];
Walter Roberson,do you know why solved by add the transpose operation ?
Walter Roberson
Walter Roberson 2019 年 1 月 7 日
If the code you posted were the only code that were in place, then it would have been correct. I suspect that you are passing those values into a function that is transposing them.

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