i need help to compute the algorithe of local AR-2D image by using blocks

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ayoub maa
ayoub maa 2018 年 12 月 23 日
コメント済み: ayoub maa 2018 年 12 月 24 日
hello everyone I want to divide an image into 8 * 8 and for each block I have to do the following steps:
calculate the least squares estimators of the AR-2D model parameter described by:
X (i, j) = teta (1.0) * X (i-1, j) + teta (0.1) * X (i, j-1) + e (i, j)
  after the calculation of teta with the method of least square I have to generate the image with this equation:
X X (i, j) = teta (1.0) * X (i-1, j) + teta (0.1) * X (i, j-1) + e (i, j)
this is my programme
clear all
clc
i=imread('D1.gif');
i= im2double(i);
x = imresize( i,0.25);
[m,n] = size(x);
noise=randn(size(x));
X = mat2cell(x, 8 * ones(1,m/8), 8 * ones(1,n/8));
X=[x(1:40,1:40)]
R = size(X, 1);
C = size(X, 2);
for i=2:R
for j=2:C
Z(i,j)=X(i-1,j)+X(i,j-1);
Z=Z+1;
end
end
teta=inv(z'*z)*z'*X
i have this message
Inner matrix dimensions must agree.
Error in Untitled2 (line 85)
teta=inv(z'*z)*z'*X
who can help me pleas to solve the probleme

回答 (1 件)

Image Analyst
Image Analyst 2018 年 12 月 24 日
See THE FAQ for processing blocks of the image.
The equation
teta=inv(z'*z)*z'*X
is the well known least squares solution, so simply use polyfit() instead of doing it yourself manually.
  1 件のコメント
ayoub maa
ayoub maa 2018 年 12 月 24 日
yes it is least squares solution but how can i use polyfit() for this equation Z(i,j)=X(i-1,j)+X(i,j-1);

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