customized 2D Cartesian plot

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BeeTiaw
BeeTiaw 2018 年 12 月 20 日
コメント済み: BeeTiaw 2018 年 12 月 20 日
Dear expert,
Could anyone help me to customize a Cartesian plot? the problem is as follow:
I have the following dataset which I want to plot into Cartesian axis.
data=[
% x y Temp
0.8470 0.0805 -0.6176
0.8476 0.1598 -0.6179
0.8477 0.2376 -0.6157
0.8471 0.3141 -0.6131
0.8466 0.3894 -0.6156
0.8469 0.4622 -0.6228
0.8477 0.5311 -0.6255
0.8480 0.5953 -0.6130
0.8472 0.6551 -0.5939
0.8461 0.7109 -0.6022
0.8465 0.7612 -0.6653
0.8485 0.8024 -0.7563
0.8492 0.8309 -0.2977
0.8431 0.8456 5.6075
0.8251 0.8494 8.3770
0.7932 0.8479 4.9443
0.7493 0.8462 3.7959
0.6973 0.8463 3.3363
0.6405 0.8475 3.1260
0.5796 0.8480 2.9271
0.5143 0.8475 2.6897
0.4443 0.8467 2.5026
0.3707 0.8467 2.4095
0.2951 0.8473 2.3851
0.2182 0.8478 2.3667
0.1401 0.8475 2.3135
0.0604 0.8469 2.2550];
The first and second colums are the coordinate of a quater-square in {x,y} and the third column is the measurement.
The value in the third column is to be plotted as shown in the figure below.
The "zero" of each "Temp" starts at the boundary of their corresponding {x,y}
How can I achieve this?
Thank you in advance...
  2 件のコメント
KALYAN ACHARJYA
KALYAN ACHARJYA 2018 年 12 月 20 日
As per what I have undestood from your question- you want to plot (x,y) position in xy plane with temp value, right?
It would be go for 3D bar plot.
Or
two yy axis, could you please clarify more (graph shown in your question)?
BeeTiaw
BeeTiaw 2018 年 12 月 20 日
Hi Kalyan,
That's correct: to plot (x,y) position in xy plane with temp value.

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回答 (1 件)

KSSV
KSSV 2018 年 12 月 20 日
x = data(:,1) ; y = data(:,2) ; z = data(:,3) ;
figure
plot3(x,y,z);
figure
scatter(x,y,20,z,'filled')
  1 件のコメント
BeeTiaw
BeeTiaw 2018 年 12 月 20 日
Thanks, but this code does not produce a 2D plot as shown in the example.

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