Extracting 2D plane values from a 3D mesh

I have 3 arrays (x,y,z) of size 243,528,000 each. These array have coordinates in x,y and z respectively. I want to extract the data in the 2D plane (say yz plane values at x = 2) from the 3D mesh. These x,y,and z arrays are used to create 3D mesh. How to perform this.

回答 (1 件)

Walter Roberson
Walter Roberson 2018 年 12 月 17 日

0 投票

If you have vectors of values, then scatteredInterpolant() or griddedInterpolant()
However in your earlier question you were dealing with a regular mesh that for whatever reason had been reshaped into vectors. If that is still the situation then you should rearrange back into a 3D shape instead of working with scattered points.
Is your grid 1825 * 2085 * 64 ?

4 件のコメント

Abhishek Saini
Abhishek Saini 2018 年 12 月 17 日
Model contain 1000*417*584 nodes in x, y and z direction respectively.
Mesh is structured. I have extracted the centroid of 8 node element and I want to extract the values in a plane.
My main objective is to find the 2D plane to implement inpolygon because it is for 2d.
Walter Roberson
Walter Roberson 2018 年 12 月 17 日
Abhishek Saini
Abhishek Saini 2018 年 12 月 18 日
I converted in to a linear vector to use it in another FE software for computaion. I want to create a semi circular notch (as a crack) by deleting elements from the mesh as shown in attached figure. So I was planning to find the plane at a particular position and then use inpolygon to find element number for deletion.Because the crack is of almost zero widht so I am afraid whether I could use the in_polyhedron funcition or not.image.png
Walter Roberson
Walter Roberson 2018 年 12 月 18 日
If the input is the full 243528000 and the grid is regular, then reshape and indexing will be much much faster.
Otherwise, use logical masks comparing to the x y z bounding box of the notch to select a small subset of the points, which you can then compare against the detailed polygon.

サインインしてコメントする。

質問済み:

2018 年 12 月 16 日

コメント済み:

2018 年 12 月 18 日

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by