hi,
Say, I have a matrix,
A B C D
-6760,691 0 -1 0
-3380,495 1 -1 1
-6760,691 0 -1 0
-3380,395 -1 0 -1
-3380,395 -1 0 -1
-6760,691 0 -1 0
-3380,495 -1 -1 1
-6760,691 0 -1 0
-3380,395 -1 0 -1
3380,195 1 0 1
And I want to get,
A B C D
-6760,691 0 -1 0
-3380,495 1 -1 1
-1 -1 1
-3380.395 -1 0 -1
3380,195 1 0 1
Here, I need to order the unique values of A which is done on the 1st column. I'll have to write the different patterns of B, C, D on the basis of same value of A. And, if there is any more repeated values of B,C,D for the same value of A, i'll have to keep only 1 pattern (row).
Can anyone please help me?

 採用された回答

Andrei Bobrov
Andrei Bobrov 2018 年 11 月 30 日
編集済み: Andrei Bobrov 2018 年 12 月 1 日

1 投票

EDIT
>> B = [-3380.5 1 -1 1
-6760.7 0 -1 0
-3380.4 -1 0 -1
-3380.4 -1 0 -1
-6760.7 0 -1 0
-3380.5 -1 -1 1
-6760.7 0 -1 0
-3380.4 -1 0 -1
3380.2 1 0 1];
>> A = unique(B,'rows')
A =
-6760.7 0 -1 0
-3380.5 -1 -1 1
-3380.5 1 -1 1
-3380.4 -1 0 -1
3380.2 1 0 1
>> A([false;diff(A(:,1)) == 0],1) = nan
A =
-6760.7 0 -1 0
-3380.5 -1 -1 1
NaN 1 -1 1
-3380.4 -1 0 -1
3380.2 1 0 1
>>

4 件のコメント

Sky Scrapper
Sky Scrapper 2018 年 11 月 30 日
編集済み: Sky Scrapper 2018 年 11 月 30 日
In my original matrix it's like a table. So, i don't have any specific column name A, B, C, D... i have just used here to explain clearly. So I can't use array. my matrix has 162 rows and 5 columns.
please help me in this regard.
Sky Scrapper
Sky Scrapper 2018 年 12 月 3 日
when i am working on my original matrix considering more columns say,
[ -3380.5 1 -1 1 0 0 0 0
-6760.7 0 -1 0 0 1 0 0
-3380.4 -1 0 -1 0 1 1 0
-3380.4 -1 0 -1 1 0 0 0
-6760.7 0 -1 0 0 0 1 0
-3380.5 -1 -1 1 1 0 1 0
-6760.7 0 -1 0 1 0 1 1
-3380.4 -1 0 -1 0 0 0 1
3380.2 1 0 1 0 1 0 1];
in this case, all rows are unique. But i would like to get,
-6760.7 0 -1 0 0 1 0 0
-3380.5 -1 -1 1 1 0 1 0
NaN 1 -1 1 0 0 0 0
-3380.4 -1 0 -1 0 1 1 0
3380.2 1 0 1 0 1 0 1
look, I would like to order unique states on the basis of 1st four column but they will take their corresponding whole rows.
Could you please solve this?
Andrei Bobrov
Andrei Bobrov 2018 年 12 月 3 日
A = [ -3380.5 1 -1 1 0 0 0 0
-6760.7 0 -1 0 0 1 0 0
-3380.4 -1 0 -1 0 1 1 0
-3380.4 -1 0 -1 1 0 0 0
-6760.7 0 -1 0 0 0 1 0
-3380.5 -1 -1 1 1 0 1 0
-6760.7 0 -1 0 1 0 1 1
-3380.4 -1 0 -1 0 0 0 1
3380.2 1 0 1 0 1 0 1];
[~,b] = unique(A(:,1:4),'rows');
B = A(b,:);
B([false;diff(B(:,1))==0],1) = nan;
Sky Scrapper
Sky Scrapper 2018 年 12 月 3 日
it's working properly. Thanks!

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