How to check the number of ones from certain row to the 1st row?

t(:,:,1) =
     1    10    19    28    37    46    55    64    73    82
     2    11    20    1     38    47    56    65    74    83
     3    12    21    30    39    48    57    66    75    84
     4    13    22    31    40    49    58    67    76    85
     5    14    1     32    41    50    59    68    77    86
     6    15    24    33    42    51    60    69    78    87
     7    16    25    34    43    1     61    70    79    88
     8    17    26    35    44    53    62    71    80    89
     9    18    27    36    45    54    63    72    81    90


t(:,:,2) =

    91   100   109   118   127   136   145   154   163   172
    92   101   110   119   128   137   146   155   164   173
    93   102   111   120   129   138   147   156   165   174
    94   103   112   121   1     139   148   157   166   175
    95   104   1     122   131   140   149   158   167   176
    96   105   114   123   132   141   150   159   168   177
    1    106   115   124   133   142   151   160   169   178
    98   107   116   125   134   143   152   161   170   179
    99   108   117   126   1     144   153   162   171   180

How to check the number of ones but starting from row 7 till the 1st row for both matrices?

Is it using for loop ?

Answer 1

[Walter Roberson]

squeeze( sum( t(1:7, :, :) == 1, 1 ) )

the result would be 10 x 2 -- the 10 columns of t and the 2 panes.

[fyza affandi]

Thank you sir.

[fyza affandi]

What if I want it by row instead of counting ones by column?

9 rows of t and the 2 panes

[Image Analyst]

Gvie numerical example, including both inputs and the desired output.

I don't even know what "row 7 till the 1st row" means. Doesn't really make sense in English. "till" usually means "until". So "row 7 until..." would mean from row 7 (inclusive) until some row larger than 7, like 8, 9, 100, etc. NOT row 1, which is in the backward/smaller direction.