I am using R2018b, and trying to use the function 'validtaestring', but it doesn't find a partial match. Has anyone tried that in this version?

1 回表示 (過去 30 日間)
STR2={'AA_UCECC'};
str='UCE';
validatestring(str,STR2)
Expected input to match one of these values:
'AA_UCECC'
The input, 'UCE', did not match any of the valid values.

採用された回答

Guy Nir
Guy Nir 2018 年 11 月 20 日
Seems like validatestring only searches first n characters. Therefore I am using strfind.
Thank you,
GUy
  2 件のコメント
Image Analyst
Image Analyst 2018 年 11 月 20 日
strfind returns an index or an empty null string.
You might want to use contains() like I did in my answer, unless you really need to know the index where the substring starts. If you have just one item, like you did, then you can also use strcmp() or ismember().

サインインしてコメントする。

その他の回答 (1 件)

Image Analyst
Image Analyst 2018 年 11 月 20 日
To find partial matches, don't use validatestring(). Use contains
validString = contains(str, STR2);

カテゴリ

Help Center および File ExchangeCharacters and Strings についてさらに検索

製品


リリース

R2018b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by