verification of the intepretation of a simple code that contains "isequalwithequalnans"
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Could you please verify the interpretation of the code
if ~(isequalwithequalnans(a, b) ==1 | isequalwithequalnans(a, c) ==1)
'not ok'
End
My interpretation is the following
If (a and b) are not equal OR (a and c) are not equal then
“Not ok”
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Andrei Bobrov
2012 年 7 月 6 日
編集済み: Andrei Bobrov
2012 年 7 月 6 日
isequalwithequalnans(a,b) | isequalwithequalnans(a,c)
4 件のコメント
C.J. Harris
2012 年 7 月 6 日
Maybe I'm missing something here, but this is still not correct. Notice the NOT symbol (~) in the original statement. Your answer is the opposite of the correct answer.
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C.J. Harris
2012 年 7 月 6 日
編集済み: C.J. Harris
2012 年 7 月 6 日
No, that interpretation is NOT correct.
The statement says if BOTH b and c are different to a then 'Not ok'. Or in other words it is 'ok' as long as either b OR c is equal to a.
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