Keep getting this error and I cannot figure out why: Dimensions of arrays being concatenated are not consistent.

1 回表示 (過去 30 日間)
I have the following code trying to solve differential equation of second order:
[t,X] = ode45(@(t,X) odefun_4(t,X,u), [0 10], [0;0]);
function dx = odefun_4(t,x,u)
%xdisp(u);
m = 15;
b = 0.2;
k = 2;
%u = interp1(ut,u,t);
dx = [x(2); u/m - (b/m)*x(2) - (k/m)*x(1)];
end
Vector u is a 1x100 vector. I expect to get a 2x100 matrix as the return value. What am I doing wrong ?

採用された回答

madhan ravi
madhan ravi 2018 年 11 月 11 日
編集済み: madhan ravi 2018 年 11 月 11 日
EDITED
m = 15;
b = 0.2;
k = 2;
ut = linspace(0, 10);
u = 5 * sin(2 * ut) + 10.5; % input of our system - external forc
dx = @(t,x,u)[x(2); u/m - (b/m)*x(2) - (k/m)*x(1)]
for u=u
[t,X] = ode45(@(t,x)dx(t,x,u), [0 10], [0;0]); %function calling
plot(t,X)
hold on
end
  11 件のコメント
madhan ravi
madhan ravi 2018 年 11 月 11 日
編集済み: madhan ravi 2018 年 11 月 11 日
Anytime :) make sure to accept the answer so that people know the question is solved

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeOrdinary Differential Equations についてさらに検索

製品


リリース

R2018a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by