How to return corresponding element in two same same size matrices

I have two 360*360 matrices (x,y). I want to find the minimum value in each column of the y matrix (YMin - 1*360) and then find the values of the corresponding elements in the x matrix (XMin - 1*360). I tried to use the row numbers but I'm missing something simple here;

 [YMin, YRow] = min(y);
 XMin = x(YRow);

Answer 1

[Guillaume]

Your x(YRow) doesn't work because matlab doesn't know that you want element YRow(1) to be taken in the first column, YRow(2) in the second column, etc. One way to solve this:

[YMin, YRow] = min(y);
XMin = x(sub2ind(size(x), YRow, 1:numel(YRow))

Or you can do the calculation that sub2ind does yourself:

XMin = x(Yrow + (0:numel(YRow)-1) * size(x, 1))

Answer 2

[madhan ravi]

a=rand(4)      %fake  datas as an example 
b=rand(4)
[values,indices]=min(a)
b(indices)=a(indices)       %corresponding elements are replaced in second matrix b

[madhan ravi]

Then find the values of the corresponding elements

Need some explanation here

you want to returns the corresponding linear index or row?

Give a short example of your output using 2 by 2 matrix

see edited answer

[Jordan Ballantyne]

 XMin = x(YRow)       %returns a 1*360 matrix
 XMin = x(YRow,:)     %returns a 360*360 matrix

I want to return a 1*360. First, the minimum element in each column and then return value in the second matrix in the same location in each column.

For example if the minimum value in column 1 of the first matrix is (179:1), then i want to return the value in (179:1) in the second matrix, for all columns.

I dont want to replace the elements in the second matrix, i want to return them into a 1*360 matrix (360 values to correspond)

 y = [1,2,3:3,2,1:2,1,3];
 x = [3,2,1:1,2,3:2,3,1];
 [YMin, YRow] = min(y);
 XMin = x(YRow);    %returns [3 2 1] instead of [3 3 3]