Hi all, I'm struggling to figure a simple method to determine the number of unique values per row in a matrix. For example in the matrix [1 2 3; 4 4 5; 6 6 6]
I would expect the result to be [3, 2, 1] I've tried using unique() and histc but neither are giving me the result I am looking for. Thanks!

2 件のコメント

Stephan
Stephan 2018 年 11 月 4 日
編集済み: Stephan 2018 年 11 月 4 日
Please explain the thoughts that lead to your expected result.
Zee Imports
Zee Imports 2018 年 11 月 4 日
Hi, As there are 3x unique values in row 1, 2x unique values in row 2 and 1x unique values in row 3.
I have basically windowed an audio signal into a matrix and am now trying to find the number of unique values in each window

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 採用された回答

Bruno Luong
Bruno Luong 2018 年 11 月 4 日

5 投票

>> A=[1 2 3; 4 4 5; 6 6 6]
A =
1 2 3
4 4 5
6 6 6
>> sum(diff(sort(A,2),1,2)~=0,2)+1
ans =
3
2
1

その他の回答 (1 件)

Walter Roberson
Walter Roberson 2018 年 11 月 4 日

1 投票

There is a vectorized way to compute this but it is not simple and it quickly gets expensive to calculate. Easier is
cellfun(@(c) length(unique(c)), num2cell(YourMatrix, 2))

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