conv2 'valid' implementation
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I need to implement the conv2 function for a the HDL coder since it's not supported, I believe that I have the main function down, what I'm struggling with is the implementation of conv2 'valid' which is described in the documentation with — Returns only parts of the convolution that are computed without zero-padded edges-
The code for conv2 is the one I'm sharing, any help would be appreciated.
function B = convolve(A, k)
[r, c] = size(A);
[m, n] = size(k);
h = rot90(k, 2);
center = floor((size(h)+1)/2);
left = center(2) - 1;
right = n - center(2);
top = center(1) - 1;
bottom = m - center(1);
Rep = zeros(r + top + bottom, c + left + right);
for x = 1 + top : r + top
for y = 1 + left : c + left
Rep(x,y) = A(x - top, y - left);
end
end
B = zeros(r , c);
for x = 1 : r
for y = 1 : c
for i = 1 : m
for j = 1 : n
q = x - 1;
w = y -1;
B(x, y) = B(x, y) + (Rep(i + q, j + w) * h(i, j));
end
end
end
end
2 件のコメント
Juan Pereira
2019 年 10 月 7 日
Useful, thank you.
Savannah Quinn
2020 年 9 月 13 日
Hello, I am trying to use this code to implement various image filters however I keep getting the an index out of bounds error due to h(i,j). Any ideas?
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その他の回答 (2 件)
Bharath Venkataraman
2018 年 11 月 2 日
編集済み: Bharath Venkataraman
2018 年 11 月 2 日
0 投票
If you are looking for conv2 for image filtering, you can use the ImageFilter block and System object in Vision HDL Toolbox.
1 件のコメント
Bharath Venkataraman
2018 年 11 月 20 日
0 投票
2 件のコメント
Alla
2018 年 11 月 29 日
Bharath Venkataraman
2018 年 11 月 29 日
conv2 with 'valid' returns a smaller image (without padding), so please make sure you are only comparing the central part of the image.
You may find it closer to matching if you use 'same' instead of 'valid'.
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