Size mismatch using reshape in HDL Coder
2 ビュー (過去 30 日間)
古いコメントを表示
I have an 8x8 input matrix, since 2D matrices aren't supproted I reshape it to 64x1 for the input and then reshape it back within the function using A=reshape(A, 8, 8); it runs well in Matlab but the code generation spits out this error:
Size mismatch (size [64 x 1] ~= size [8 x 8]). The size to the left is the size of the left-hand side of the assignment.
What's odd is that the problem seems to have came out of nowhere because I'm almost certain It was working well and I didn't change anything then it just started to error.
0 件のコメント
採用された回答
Bharath Venkataraman
2018 年 11 月 2 日
Could you try assigning the value to a different variable rather than back to A. Ar = reshape(A,8,8);
use Ar in the code below.
2 件のコメント
その他の回答 (0 件)
参考
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!