Create contents of popup menu dynamically
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I want to create a popup menu with contents dynamically,based on value of a variable n in my code.
Example:- If n is 2,the contents should be Data1,Data2.
If n is 3,the contents should be Data1,Data2,Data3.
...................................................
If n is x,the contents should be Data1,Data2,......Datax
2 件のコメント
Jan
2012 年 7 月 4 日
Ok. What have you tried so far and what problems occurred? Did you read "doc uicontrol" already?
採用された回答
Mark Whirdy
2012 年 7 月 4 日
Hi Luffy
Not 100% sure I understand the degree of dynamism you're going for but stick the code below underneath whereever n changes (assuming handles is in scope there). Here you specify the menu contents cell array explicity in each case - does this fit your use-case?
switch n case 1 set(handles.popupmenu1,'String',{'Data1';'Data2'},'Value',1); case 2 set(handles.popupmenu1,'String',{'Data1';'Data2';'Data3'},'Value',1); end
Alternatively, if for some reason you're defining the contents to be a cellaray of 'Data#' whose length = n, then the code below should do it
n = 4; myarray = strcat('Data',cellfun(@num2str,num2cell((1:n)'),'UniformOutput',false)) set(handles.popupmenu1,'String',myarray,'Value',1);
All the best Mark
2 件のコメント
その他の回答 (1 件)
Jan
2012 年 7 月 5 日
String = sprintf('Data%d#', 1:n);
String(end) = [];
CString = regexp(String, '#', 'split');
uicontrol('Style', 'popupmenu', ...
'String', String, ...
'Units', 'pixels', ...
'Position', [370, 60, 95, 21]);
3 件のコメント
Samuel Hirsbrunner
2016 年 7 月 23 日
finde this on my researches... I may shorten the code again:
String = sprintf('Data%d\n',1:size(Data))
by adding "\n" it made a new line on each value. so no need for the regesp() at least i think this works...
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