innerIntegral = 
viewSolid is not working
古いコメントを表示
Its not working in my Matlab app.Its showing invalid function.What can i do
回答 (2 件)
Walter Roberson
2018 年 10 月 14 日
0 投票
viewSolidone is not part of MATLAB.
2 件のコメント
Tansheed
2023 年 12 月 21 日
I did download it and moved it into the same file with the matlab files just as my lecturer instructed me to do. But it still shows invalid to me but in my peers comupters it succesfully executes the action
Tansheed
2023 年 12 月 21 日
Please tell us the possible reasons and how to slove them
clc;
clear all;
syms x y z
value = int(int(6*x*y, z, 0, 1 + x + y), y, 0, sqrt(x),x,0,1
viewSolid(z,0,1+x+y,y,0*x,sqrt(x),x,0,1);
1 件のコメント
This line of code (commented out so I can run other commands later in the comment) is not syntactically valid, as it has three ( and two ). I assume you ran it and then deleted one of the closing parentheses. Where was that closing parenthesis? Was it at the end of the line?
%{
value = int(int(6*x*y, z, 0, 1 + x + y), y, 0, sqrt(x),x,0,1
%}
If it was, the inner call to int looks fine. [Since z doesn't appear in 6*x*y, you're integrating a constant.]
syms x y z
innerIntegral = int(6*x*y, z, 0, 1 + x + y)
If you're trying to perform a triple integral, the innermost one over z, the middle one over y, and the outermost over x, you're missing two closing parentheses and an extra int( call.
middleIntegral = int(innerIntegral, y, 0, sqrt(x))
outerIntegral = int(middleIntegral, x, 0, 1)
Or putting them all together in one line:
% Added vvvv v v
value = int(int(int(6*x*y, z, 0, 1 + x + y), y, 0, sqrt(x)),x,0,1)
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